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Popular >

t^2y^{''}-2y=0

Solution

t^{2} y^{^{''}} - 2 y = 0

Solution

y = c_{1} t^{2} + \frac{c _{2}}{t}

Solution steps

t^{2} y^{''} (t) - 2 y = 0

Solve linear ODE:

y = c_{1} t^{2} + \frac{c _{2}}{t}

y = c_{1} t^{2} + \frac{c _{2}}{t}

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Frequently Asked Questions (FAQ)

What is the solution for t^2y^{''}-2y=0 ?
The solution for t^2y^{''}-2y=0 is y=c_{1}t^2+(c_{2})/t