What is the sum from n=8 to infinity of (1/4)^n ?

The sum from n=8 to infinity of (1/4)^n is converges

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

sum from n=8 to infinity of (1/4)^n

n = 8 \sum \infty (\frac{1}{4})^{n}

converges

Solution steps

n = 8 \sum \infty (\frac{1}{4})^{n}

Apply Series Ratio Test:

converges

= converges

\int csc^{2} (k x) d x

\frac{7 x ^{2}}{x}

\frac{d}{d x} (\frac{x ^{2}}{4} + 2 x + 3)

\int \frac{1}{x ^{2} - 7 x + 10} d x

\frac{d}{d y} (x^{2} - 3 y^{2})

What is the sum from n=8 to infinity of (1/4)^n ?
The sum from n=8 to infinity of (1/4)^n is converges