What is the integral from 0 to 6.25 of-x^2+5x ?

The integral from 0 to 6.25 of-x^2+5x is 16.27604…

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integral from 0 to 6.25 of-x^2+5x

\int_{0}^{6.25} - x^{2} + 5 x d x

16.27604 \dots

Solution steps

\int_{0}^{6.25} - x^{2} + 5 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{6.25} x^{2} d x + \int_{0}^{6.25} 5 x d x

\int_{0}^{6.25} x^{2} d x = 81.38020 \dots

\int_{0}^{6.25} 5 x d x = 97.65625

= - 81.38020 \dots + 97.65625

Simplify

= 16.27604 \dots

\int 15 x^{\frac{1}{4}} d x

\frac{d}{d x} (arctan (x^{5}))

\frac{\partial}{\partial y} (y^{2 x})

x \to - 2 lim (4 x^{3} + 4 x - 2)

What is the integral from 0 to 6.25 of-x^2+5x ?
The integral from 0 to 6.25 of-x^2+5x is 16.27604…