What is the integral of (sec^2(x)e^{tan(x)}) ?

The integral of (sec^2(x)e^{tan(x)}) is e^{tan(x)}+C

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integral of (sec^2(x)e^{tan(x)})

\int (sec^{2} (x) e^{t a n (x)}) d x

e^{t a n (x)} + C

Solution steps

\int sec^{2} (x) e^{t a n (x)} d x

Apply u-substitution

: \int e^{u} d u

= \int e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= e^{u}

Substitute back

u = tan (x)

= e^{t a n (x)}

Add a constant to the solution

= e^{t a n (x)} + C

\frac{x}{x + 4}

lo g_{8} (2 x^{3} + 3 x^{2} + 1)

\int \frac{4 x ^{2} - 9}{x ^{3}} d x

x \to 0 lim (x)

x \to 1 lim (\frac{1}{∣ x - 1 ∣})

What is the integral of (sec^2(x)e^{tan(x)}) ?
The integral of (sec^2(x)e^{tan(x)}) is e^{tan(x)}+C