What is the integral of (3x^2-6x+2) ?

The integral of (3x^2-6x+2) is x^3-3x^2+2x+C

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integral of (3x^2-6x+2)

\int (3 x^{2} - 6 x + 2) d x

x^{3} - 3 x^{2} + 2 x + C

Solution steps

\int 3 x^{2} - 6 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int 3 x^{2} d x - \int 6 x d x + \int 2 d x

\int 3 x^{2} d x = x^{3}

\int 6 x d x = 3 x^{2}

\int 2 d x = 2 x

= x^{3} - 3 x^{2} + 2 x

Add a constant to the solution

= x^{3} - 3 x^{2} + 2 x + C

f (x) = 2 - 5 x^{2}, (- 2, - 18)

\frac{x - 2}{( x + 2 ) ( x - 3 )}

y^{^{'}} = \frac{2 y}{x}, y (\frac{1}{2}) = 5

x \to 0 lim (\frac{( x ^{3} )}{x})

\int_{- 1}^{3} x d x

What is the integral of (3x^2-6x+2) ?
The integral of (3x^2-6x+2) is x^3-3x^2+2x+C