What is the limit as e^{e^x} approaches 0+of (e^{e^x-2})/2 ?

The limit as e^{e^x} approaches 0+of (e^{e^x-2})/2 is (e^{e^{e^{e^x}}-2})/2

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limit as e^{e^x} approaches 0+of (e^{e^x-2})/2

e^{e^{e^{e^{x}}}} \to 0 + lim \frac{e ^{e^{e^{e^{x}}} - 2}}{2}

\frac{e ^{e^{e^{e^{x}}} - 2}}{2}

Solution steps

e^{e^{e^{e^{x}}}} \to 0 + lim \frac{e ^{e^{e^{e^{x}}} - 2}}{2}

x \to a lim c = c

= \frac{e ^{e^{e^{e^{x}}} - 2}}{2}

\frac{d}{d x} (cot (6 x - x^{2}))

x \cdot sin (\frac{1}{x})

y = x^{3} - 11 x^{2} + 30 x, y = - x^{3} + 11 x^{2} - 30 x

f (x) = 3 - e^{- x}

\frac{d}{d x} (3 7 x)

What is the limit as e^{e^x} approaches 0+of (e^{e^x-2})/2 ?
The limit as e^{e^x} approaches 0+of (e^{e^x-2})/2 is (e^{e^{e^{e^x}}-2})/2