What is the derivative of 2+|x-3| ?

The derivative of 2+|x-3| is (x-3)/(|x-3|)

What is the first derivative of 2+|x-3| ?

The first derivative of 2+|x-3| is (x-3)/(|x-3|)

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\frac{d}{d x} (2 + ∣ x - 3 ∣)

\frac{x - 3}{∣ x - 3 ∣}

Solution steps

\frac{d}{d x} (2 + ∣ x - 3 ∣)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (2) + \frac{d}{d x} (∣ x - 3 ∣)

\frac{d}{d x} (2) = 0

\frac{d}{d x} (∣ x - 3 ∣) = \frac{x - 3}{∣ x - 3 ∣}

= 0 + \frac{x - 3}{∣ x - 3 ∣}

Simplify

= \frac{x - 3}{∣ x - 3 ∣}

\int \frac{7}{x - 6} d x

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\frac{d}{d x} (ln (2 x^{3}))

\frac{\partial}{\partial x} (\frac{y ^{2}}{x + y})

\frac{d}{d x} (\frac{sin ( x ) cos ( x )}{2 x ^{2}})

What is the derivative of 2+|x-3| ?
The derivative of 2+|x-3| is (x-3)/(|x-3|)
What is the first derivative of 2+|x-3| ?
The first derivative of 2+|x-3| is (x-3)/(|x-3|)