What is area x^4-2x^2,2x^2,[-2,0] ?

The answer to area x^4-2x^2,2x^2,[-2,0] is 64/15

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area x^4-2x^2,2x^2,[-2,0]

area

x^{4} - 2 x^{2}, 2 x^{2}, [- 2, 0]

\frac{64}{15}

Decimal

4.26666 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{0} x^{4} - 4 x^{2} d x

Solve

\int_{- 2}^{0} x^{4} - 4 x^{2} d x : \frac{64}{15}

The area is:

= \frac{64}{15}

\int 5 x - x^{2} d x

\int \frac{( x + 2 )}{( x ^{2} + 2 x + 10 ) ^{\frac{5}{2}}} d x

\int_{- 2}^{0} (x^{3} - 4 x) d x

\frac{e ^{- 2 s}}{s}

y^{^{'}} = 2 x (1 + x^{2} - y), y (1) = 2

What is area x^4-2x^2,2x^2,[-2,0] ?
The answer to area x^4-2x^2,2x^2,[-2,0] is 64/15