What is the f(x)=(1+x+x^2)^{99} ?

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f(x)=(1+x+x^2)^{99}

f (x) = (1 + x + x^{2})^{99}

Domain : - \infty < x < \infty

Range : f (x) \geq \frac{3 ^{99}}{4 ^{99}}

Y Intercepts : (0, 1)

Asymptotes : None

Extreme Points : Minimum (- \frac{1}{2}, \frac{3 ^{99}}{4 ^{99}})

Interval Notation

Domain : (- \infty, \infty)

Solution steps

Domain of

(1 + x + x^{2})^{99} : - \infty < x < \infty

Range of

(1 + x + x^{2})^{99} : f (x) \geq \frac{3 ^{99}}{4 ^{99}}

Axis interception points of

(1 + x + x^{2})^{99} :

Y Intercepts

: (0, 1)

Asymptotes of

(1 + x + x^{2})^{99} :

None

Extreme Points of

(1 + x + x^{2})^{99} :

Minimum

(- \frac{1}{2}, \frac{3 ^{99}}{4 ^{99}})

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