What is the solution for (10y^2-xy)dx+x^2dy=0 ?

The solution for (10y^2-xy)dx+x^2dy=0 is y= x/(10ln(x)+c_{1)}

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(10y^2-xy)dx+x^2dy=0

(10 y^{2} - x y) d x + x^{2} d y = 0

y = \frac{x}{10 ln ( x ) + c _{1}}

Solution steps

(10 y^{2} - x y) d x + x^{2} d y = 0

Solve Bernoulli ODE:

y = \frac{x}{10 ln ( x ) + c _{1}}

y = \frac{x}{10 ln ( x ) + c _{1}}

x \to \infty lim (6 x^{2})

n = 0 \sum \infty \frac{1}{1 + ln ( n )}

\int_{2}^{3} \frac{2}{x ^{2} - 1} d x

\int x^{2} - 2 x d x

\int c x d x

What is the solution for (10y^2-xy)dx+x^2dy=0 ?
The solution for (10y^2-xy)dx+x^2dy=0 is y= x/(10ln(x)+c_{1)}