What is the tangent of y=F-x^2-x,\at x=-2 ?

The tangent of y=F-x^2-x,\at x=-2 is (2a-d/(da)(F(b,a))+1)(x-a)+(-d/(db)(F(b,a))+1)(y-b)=0

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tangent of y=F-x^2-x,\at x=-2

tangent of

y = F (y, x) - x^{2} - x, at x = - 2

(2 a - \frac{d}{d a} (F (b, a)) + 1) (x - a) + (- \frac{d}{d b} (F (b, a)) + 1) (y - b) = 0

Solution steps

y = F (y, x) - x^{2} - x

Rewrite as

- F (y, x) + x + x^{2} + y = 0

Find the gradient to the conic function

- F (y, x) + x + x^{2} + y = 0

at point

(a, b)

v = (2 a - \frac{d}{d a} (F (b, a)) + 1, - \frac{d}{d b} (F (b, a)) + 1)

Find he tangent to the conic function

- F (y, x) + x + x^{2} + y = 0

at the point

(a, b)

(2 a - \frac{d}{d a} (F (b, a)) + 1) (x - a) + (- \frac{d}{d b} (F (b, a)) + 1) (y - b) = 0

f (x) = 10 t

y^{^{'}} = x + 4 y

n = 0 \sum \infty 2 n

x + 20, x^{2}

\frac{d}{d x} ((2 x + 1)^{2})

What is the tangent of y=F-x^2-x,\at x=-2 ?
The tangent of y=F-x^2-x,\at x=-2 is (2a-d/(da)(F(b,a))+1)(x-a)+(-d/(db)(F(b,a))+1)(y-b)=0