What is the solution for t(dy)/(dt)=t^3+18t^3y ?

The solution for t(dy)/(dt)=t^3+18t^3y is y=(e^{6t^3+c_{1}})/(18)-1/18

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t(dy)/(dt)=t^3+18t^3y

t \frac{d y}{d t} = t^{3} + 18 t^{3} y

y = \frac{e ^{6 t^{3} + c_{1}}}{18} - \frac{1}{18}

Solution steps

t \frac{d y}{d t} = t^{3} + 18 t^{3} y

Solve separable ODE:

y = \frac{e ^{6 t^{3} + c_{1}}}{18} - \frac{1}{18}

y = \frac{e ^{6 t^{3} + c_{1}}}{18} - \frac{1}{18}

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What is the solution for t(dy)/(dt)=t^3+18t^3y ?
The solution for t(dy)/(dt)=t^3+18t^3y is y=(e^{6t^3+c_{1}})/(18)-1/18