What is the integral from-1 to 1 of (\sqrt[3]{t}-5) ?

The integral from-1 to 1 of (\sqrt[3]{t}-5) is -10

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integral from-1 to 1 of (\sqrt[3]{t}-5)

\int_{- 1}^{1} (3 t - 5) d t

- 10

Solution steps

\int_{- 1}^{1} 3 t - 5 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 3 t d t - \int_{- 1}^{1} 5 d t

\int_{- 1}^{1} 3 t d t = 0

\int_{- 1}^{1} 5 d t = 10

= 0 - 10

Simplify

= - 10

\int \frac{( 1 + ln ( x ) ) ^{3}}{x} d x

\int (3 x + 1) (4 - x) d x

\frac{( x - 2 )}{x + 3}

\frac{d}{d x} (3 x y)

\frac{2 x}{( x ^{2} + 4 ) ^{2}}

What is the integral from-1 to 1 of (\sqrt[3]{t}-5) ?
The integral from-1 to 1 of (\sqrt[3]{t}-5) is -10