What is the derivative of 16-x^{2/3} ?

The derivative of 16-x^{2/3} is -2/(3x^{1/3)}

What is the first derivative of 16-x^{2/3} ?

The first derivative of 16-x^{2/3} is -2/(3x^{1/3)}

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\frac{d}{d x} (16 - x^{\frac{2}{3}})

- \frac{2}{3 x ^{\frac{1}{3}}}

Solution steps

\frac{d}{d x} (16 - x^{\frac{2}{3}})

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (16) - \frac{d}{d x} (x^{\frac{2}{3}})

\frac{d}{d x} (16) = 0

\frac{d}{d x} (x^{\frac{2}{3}}) = \frac{2}{3 x ^{\frac{1}{3}}}

= 0 - \frac{2}{3 x ^{\frac{1}{3}}}

Simplify

= - \frac{2}{3 x ^{\frac{1}{3}}}

cos ((π x)^{6})

\frac{d}{d x} (x x^{2} - 16)

\frac{10}{s ^{2} + s + 10}

\frac{d}{d x} (e^{2 x} + 1)

f (x) = \frac{3}{x + 1}, at x = 7

What is the derivative of 16-x^{2/3} ?
The derivative of 16-x^{2/3} is -2/(3x^{1/3)}
What is the first derivative of 16-x^{2/3} ?
The first derivative of 16-x^{2/3} is -2/(3x^{1/3)}