What is the solution for t(dy)/(dt)+(t+1)y=2te^{-t} ?

The solution for t(dy)/(dt)+(t+1)y=2te^{-t} is y= t/(e^t)+(c_{1})/(e^tt)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

t(dy)/(dt)+(t+1)y=2te^{-t}

t \frac{d y}{d t} + (t + 1) y = 2 t e^{- t}

y = \frac{t}{e ^{t}} + \frac{c _{1}}{e ^{t} t}

Solution steps

t \frac{d y}{d t} + (t + 1) y = 2 t e^{- t}

Solve linear ODE:

y = \frac{t}{e ^{t}} + \frac{c _{1}}{e ^{t} t}

y = \frac{t}{e ^{t}} + \frac{c _{1}}{e ^{t} t}

\int \frac{1 + x}{1 - x} d x

\int \frac{13 e ^{- 5 x} cos ( x )}{10} d x

x \cdot cos (2 x)

\int \frac{8 ln ( x + 9 )}{x ^{2}} d x

6 sin (2 t)

What is the solution for t(dy)/(dt)+(t+1)y=2te^{-t} ?
The solution for t(dy)/(dt)+(t+1)y=2te^{-t} is y= t/(e^t)+(c_{1})/(e^tt)