What is (\partial)/(\partial z)(x+y+z) ?

The answer to (\partial)/(\partial z)(x+y+z) is 1

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(\partial)/(\partial z)(x+y+z)

\frac{\partial}{\partial z} (x + y + z)

1

Solution steps

\frac{\partial}{\partial z} (x + y + z)

Treat

x, y

as constants

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial z} (x) + \frac{\partial}{\partial z} (y) + \frac{\partial}{\partial z} (z)

\frac{\partial}{\partial z} (x) = 0

\frac{\partial}{\partial z} (y) = 0

\frac{\partial}{\partial z} (z) = 1

= 0 + 0 + 1

Simplify

= 1

\int e^{a t} d t

\frac{\partial}{\partial x} (\frac{1}{4} 2^{x} y^{3})

\int \frac{1}{16 + x ^{2}} d x

\frac{\partial}{\partial y} (8 x y - \frac{1}{4} (x + y)^{4})

x \to x lim (sin (x))

What is (\partial)/(\partial z)(x+y+z) ?
The answer to (\partial)/(\partial z)(x+y+z) is 1