What is area 2x^2,2x+6,-2,-1 ?

The answer to area 2x^2,2x+6,-2,-1 is (17-5sqrt(13))/3+6sqrt(13)-19

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area 2x^2,2x+6,-2,-1

area

2 x^{2}, 2 x + 6, - 2, - 1

\frac{17 - 5 13}{3} + 613 - 19

Decimal

2.29072 \dots

Solution steps

Apply the area formula:

\int_{- 2}^{- 1} 2 x^{2} - (2 x + 6) d x

Solve

\int_{- 2}^{- 1} 2 x^{2} - (2 x + 6) d x : \frac{17 - 5 13}{3} + 613 - 19

The area is:

= \frac{17 - 5 13}{3} + 613 - 19

x \to \infty lim (e^{3 x})

x \to 8 + lim (\frac{2}{x - 8})

(x - 1) ln (x - 1), 2

y^{^{''}} + 16 y = 40 sin (4 t)

\frac{\partial}{\partial y} (e^{x} + e^{y})

What is area 2x^2,2x+6,-2,-1 ?
The answer to area 2x^2,2x+6,-2,-1 is (17-5sqrt(13))/3+6sqrt(13)-19