What is the derivative of 3x^2+8x-25 ?

The derivative of 3x^2+8x-25 is 6x+8

What is the first derivative of 3x^2+8x-25 ?

The first derivative of 3x^2+8x-25 is 6x+8

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derivative of

3 x^{2} + 8 x - 25

6 x + 8

Solution steps

\frac{d}{d x} (3 x^{2} + 8 x - 25)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (3 x^{2}) + \frac{d}{d x} (8 x) - \frac{d}{d x} (25)

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (25) = 0

= 6 x + 8 - 0

Simplify

= 6 x + 8

\int 4 x^{2} + 3 d x

w (z) = \frac{3 z}{1 + 2 z}

x \to \infty lim (- 8)

cos (x), x^{2} + 2, [0, 2]

\int e^{- 2 x^{2}} d x

What is the derivative of 3x^2+8x-25 ?
The derivative of 3x^2+8x-25 is 6x+8
What is the first derivative of 3x^2+8x-25 ?
The first derivative of 3x^2+8x-25 is 6x+8