What is the solution for (x^2+y^2)dx=2xydy ?

The solution for (x^2+y^2)dx=2xydy is y=sqrt(x^2+c_{1)x},y=-sqrt(x^2+c_{1)x}

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(x^2+y^2)dx=2xydy

(x^{2} + y^{2}) d x = 2 x y d y

y = x^{2} + c_{1} x, y = - x^{2} + c_{1} x

Solution steps

(x^{2} + y^{2}) d x = 2 x y d y

Solve Bernoulli ODE:

y = x^{2} + c_{1} x, y = - x^{2} + c_{1} x

y = x^{2} + c_{1} x, y = - x^{2} + c_{1} x

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\int \frac{1}{x ^{\frac{2}{3}} ( 2 + x ^{\frac{1}{3}} )} d x

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What is the solution for (x^2+y^2)dx=2xydy ?
The solution for (x^2+y^2)dx=2xydy is y=sqrt(x^2+c_{1)x},y=-sqrt(x^2+c_{1)x}