What is the derivative of f(x)=sqrt(4x+1) ?

The derivative of f(x)=sqrt(4x+1) is 2/(sqrt(4x+1))

What is the first derivative of f(x)=sqrt(4x+1) ?

The first derivative of f(x)=sqrt(4x+1) is 2/(sqrt(4x+1))

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derivative of

f (x) = 4 x + 1

\frac{2}{4 x + 1}

Solution steps

\frac{d}{d x} (4 x + 1)

Apply the chain rule:

\frac{1}{2 4 x + 1} \frac{d}{d x} (4 x + 1)

= \frac{1}{2 4 x + 1} \frac{d}{d x} (4 x + 1)

\frac{d}{d x} (4 x + 1) = 4

= \frac{1}{2 4 x + 1} \cdot 4

Simplify

\frac{1}{2 4 x + 1} \cdot 4 : \frac{2}{4 x + 1}

= \frac{2}{4 x + 1}

\int \frac{( x ^{3} + 16 )}{x ^{2} + 16} d x

\int - tan (x) + C d x

\int x \cdot cos (8 x^{2} + π) d x

9 1 + x

sin^{3} (4 x)

What is the derivative of f(x)=sqrt(4x+1) ?
The derivative of f(x)=sqrt(4x+1) is 2/(sqrt(4x+1))
What is the first derivative of f(x)=sqrt(4x+1) ?
The first derivative of f(x)=sqrt(4x+1) is 2/(sqrt(4x+1))