What is the integral of 2/(4+x^2) ?

The integral of 2/(4+x^2) is arctan(x/2)+C

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integral of 2/(4+x^2)

\int \frac{2}{4 + x ^{2}} d x

arctan (\frac{x}{2}) + C

Solution steps

\int \frac{2}{4 + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int \frac{1}{4 + x ^{2}} d x

Apply Integral Substitution

= 2 \cdot \int \frac{1}{2 ( u ^{2} + 1 )} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \frac{1}{2} \cdot \int \frac{1}{u ^{2} + 1} d u

Use the common integral:

\int \frac{1}{u ^{2} + 1} d u = arctan (u)

= 2 \cdot \frac{1}{2} arctan (u)

Substitute back

u = \frac{x}{2}

= 2 \cdot \frac{1}{2} arctan (\frac{x}{2})

Simplify

2 \cdot \frac{1}{2} arctan (\frac{x}{2}) : arctan (\frac{x}{2})

= arctan (\frac{x}{2})

Add a constant to the solution

= arctan (\frac{x}{2}) + C

y = \frac{1}{x}, y = x, y = 2

\int 2^{x} ln (2) d x

\int x y e^{z} d z

\frac{d y}{d x} = k (y - 80)

x^{2} (x^{2} - 4)