What is the derivative of \sqrt[4]{t} ?

The derivative of \sqrt[4]{t} is 1/(4t^{3/4)}

What is the first derivative of \sqrt[4]{t} ?

The first derivative of \sqrt[4]{t} is 1/(4t^{3/4)}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

derivative of

4 t

\frac{1}{4 t ^{\frac{3}{4}}}

Solution steps

\frac{d}{d t} (4 t)

Apply radical rule:

n a = a^{\frac{1}{n}}

= \frac{d}{d t} (t^{\frac{1}{4}})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= \frac{1}{4} t^{\frac{1}{4} - 1}

Simplify

\frac{1}{4} t^{\frac{1}{4} - 1} : \frac{1}{4 t ^{\frac{3}{4}}}

= \frac{1}{4 t ^{\frac{3}{4}}}

ln (x^{2} + 5)

x \to 0 lim ((1 + \frac{3}{x ^{4}})^{x})

\frac{d}{d x} (x^{4} - 6 x - 9)

x y^{^{'}} - 3 y^{^{'}} - (x - 3) cos (x) + y = 0

\int \frac{e ^{t}}{t} d t

What is the derivative of \sqrt[4]{t} ?
The derivative of \sqrt[4]{t} is 1/(4t^{3/4)}
What is the first derivative of \sqrt[4]{t} ?
The first derivative of \sqrt[4]{t} is 1/(4t^{3/4)}