What is the integral from 0 to 1 of 1/(x^5) ?

The integral from 0 to 1 of 1/(x^5) is diverges

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integral from 0 to 1 of 1/(x^5)

\int_{0}^{1} \frac{1}{x ^{5}} d x

diverges

Solution steps

\int_{0}^{1} \frac{1}{x ^{5}} d x

Apply the Power Rule

: [- \frac{1}{4 x ^{4}}]_{0}^{1}

= [- \frac{1}{4 x ^{4}}]_{0}^{1}

Compute the boundaries:

diverges

= diverges

5 t \frac{d y}{d t} + y = t^{4}

h \to 0 lim (\frac{ln ( e + h ) - 1}{h})

\frac{d}{d x} (3 x^{2} + \frac{2}{x} - \frac{1}{x ^{2}})

\int_{1}^{e} \frac{- 2 ln ( x )}{x ^{2}} d x

\int \frac{x}{1 + sin ( x )} d x

What is the integral from 0 to 1 of 1/(x^5) ?
The integral from 0 to 1 of 1/(x^5) is diverges