What is the tangent of f(x)=4+5x^2,(0,4) ?

The tangent of f(x)=4+5x^2,(0,4) is y=4

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tangent of f(x)=4+5x^2,(0,4)

tangent of

f (x) = 4 + 5 x^{2}, (0, 4)

y = 4

Solution steps

Find the slope of

f (x) = 4 + 5 x^{2} : \frac{df ( x )}{d x} = 10 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = 0

Find the line with slope m=

0

and passing through

(0, 4) : y = 4

y = 4

y^{^{''}} + 2 y^{^{'}} + 5 y = 8 sin (2 t)

\frac{\partial}{\partial x} (y cos (x) + 2 x e^{y})

\int_{0}^{25} \frac{1}{25 - x} d x

\int 12 x e^{6 x} d x

\frac{\partial}{\partial y} (x e^{y} + y)

What is the tangent of f(x)=4+5x^2,(0,4) ?
The tangent of f(x)=4+5x^2,(0,4) is y=4