What is the integral of 2/(sqrt(4x^2+4)) ?

The integral of 2/(sqrt(4x^2+4)) is ln|sqrt(x^2+1)+x|+C

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integral of 2/(sqrt(4x^2+4))

\int \frac{2}{4 x ^{2} + 4} d x

ln x^{2} + 1 + x + C

Solution steps

\int \frac{2}{4 x ^{2} + 4} d x

Simplify

\frac{2}{4 x ^{2} + 4} : \frac{1}{x ^{2} + 1}

= \int \frac{1}{x ^{2} + 1} d x

Use the common integral:

\int \frac{1}{x ^{2} + 1} d x = ln x^{2} + 1 + x

= ln x^{2} + 1 + x

Add a constant to the solution

= ln x^{2} + 1 + x + C

\int_{l n (3)}^{l n (5)} e^{2 x} d x

f (x) = 3^{x}, at x = 0

\int - 9 sin (3 t) d t

x \to 1 lim (x^{17} - x + 3)

What is the integral of 2/(sqrt(4x^2+4)) ?
The integral of 2/(sqrt(4x^2+4)) is ln|sqrt(x^2+1)+x|+C