What is the derivative of (sqrt(9-x^2)/(32x)) ?

The derivative of (sqrt(9-x^2)/(32x)) is -9/(32x^2sqrt(9-x^2))

What is the first derivative of (sqrt(9-x^2)/(32x)) ?

The first derivative of (sqrt(9-x^2)/(32x)) is -9/(32x^2sqrt(9-x^2))

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\frac{d}{d x} (\frac{9 - x ^{2}}{32 x})

- \frac{9}{32 x ^{2} 9 - x ^{2}}

Solution steps

\frac{d}{d x} (\frac{9 - x ^{2}}{32 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{32} \frac{d}{d x} (\frac{9 - x ^{2}}{x})

Apply the Quotient Rule:

(\frac{f}{g})^{'} = \frac{f ^{'} \cdot g - g ^{'} \cdot f}{g ^{2}}

= \frac{1}{32} \cdot \frac{\frac{d}{d x} ( 9 - x ^{2} ) x - \frac{d x}{d x} 9 - x ^{2}}{x ^{2}}

\frac{d}{d x} (9 - x^{2}) = - \frac{x}{9 - x ^{2}}

\frac{d x}{d x} = 1

= \frac{1}{32} \cdot \frac{( - \frac{x}{9 - x ^{2}} ) x - 1 \cdot 9 - x ^{2}}{x ^{2}}

Simplify

\frac{1}{32} \cdot \frac{( - \frac{x}{9 - x ^{2}} ) x - 1 \cdot 9 - x ^{2}}{x ^{2}} : - \frac{9}{32 x ^{2} 9 - x ^{2}}

= - \frac{9}{32 x ^{2} 9 - x ^{2}}

s (t) = 14 t^{2} + 840 t

0

x \to 0 lim (\frac{0 \cdot x ^{6}}{x ^{9}})

3 y^{^{''}} + 75 y = 0

f (x) = 4 - \frac{20}{x ^{3}} + \frac{3}{x ^{5}}

What is the derivative of (sqrt(9-x^2)/(32x)) ?
The derivative of (sqrt(9-x^2)/(32x)) is -9/(32x^2sqrt(9-x^2))
What is the first derivative of (sqrt(9-x^2)/(32x)) ?
The first derivative of (sqrt(9-x^2)/(32x)) is -9/(32x^2sqrt(9-x^2))