What is the tangent of-7x^4+11x^2-4 ?

The tangent of-7x^4+11x^2-4 is y=(-28a_{0}^3+22a_{0})x+21a_{0}^4-11a_{0}^2-4

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tangent of-7x^4+11x^2-4

tangent of

- 7 x^{4} + 11 x^{2} - 4

y = (- 28 a_{0}^{3} + 22 a_{0}) x + 21 a_{0}^{4} - 11 a_{0}^{2} - 4

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 7 a_{0}^{4} + 11 a_{0}^{2} - 4)

Find the slope of

y = - 7 x^{4} + 11 x^{2} - 4 : \frac{d y}{d x} = - 28 x^{3} + 22 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 28 a_{0}^{3} + 22 a_{0}

Find the line with slope m=

- 28 a_{0}^{3} + 22 a_{0}

and passing through

(a_{0}, - 7 a_{0}^{4} + 11 a_{0}^{2} - 4) : y = (- 28 a_{0}^{3} + 22 a_{0}) x + 21 a_{0}^{4} - 11 a_{0}^{2} - 4

y = (- 28 a_{0}^{3} + 22 a_{0}) x + 21 a_{0}^{4} - 11 a_{0}^{2} - 4

\int \frac{x ^{2}}{( 1 + 9 x ^{2} ) ^{\frac{3}{2}}} d x

x \to 6 lim ((x - 2)^{2})

4 (\frac{d y}{d x}) - (y) - x = 0

\frac{d y}{d x} x + x y = 1 - y

y = x^{2} + 12 x - 3

What is the tangent of-7x^4+11x^2-4 ?
The tangent of-7x^4+11x^2-4 is y=(-28a_{0}^3+22a_{0})x+21a_{0}^4-11a_{0}^2-4