What is laplacetransform 1-e^{-,\at} ?

The answer to laplacetransform 1-e^{-,\at} is 1/s-(e^{-,\at})/s

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laplacetransform 1-e^{-,\at}

laplace transform

1 - e^{-, at}

\frac{1}{s} - \frac{e ^{-, at}}{s}

Solution steps

L {1 - e^{-, at}}

Use the linearity property of Laplace Transform:

For functions

f (t), g (t)

and constants

a, b : L {a \cdot f (t) + b \cdot g (t)} = a \cdot L {f (t)} + b \cdot L {g (t)}

= L {1} - L {e^{-, at}}

L {1} : \frac{1}{s}

L {e^{-, at}} : \frac{e ^{-, at}}{s}

= \frac{1}{s} - \frac{e ^{-, at}}{s}

\int \frac{1}{( x + 2 ) ^{3}} d x

f (x) = \frac{x}{x + 3}

\frac{\partial}{\partial x} (e^{ik x})

\int (1 + sin^{2} (x)) d x

\frac{d}{d x} (ln ((x - 4)^{3}))

What is laplacetransform 1-e^{-,\at} ?
The answer to laplacetransform 1-e^{-,\at} is 1/s-(e^{-,\at})/s