What is the derivative of f(x)=x^2+2x ?

The derivative of f(x)=x^2+2x is 2x+2

What is the first derivative of f(x)=x^2+2x ?

The first derivative of f(x)=x^2+2x is 2x+2

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derivative of

f (x) = x^{2} + 2 x

2 x + 2

Solution steps

\frac{d}{d x} (x^{2} + 2 x)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{2}) + \frac{d}{d x} (2 x)

\frac{d}{d x} (x^{2}) = 2 x

\frac{d}{d x} (2 x) = 2

= 2 x + 2

\frac{d}{d x} (\frac{x ^{2} + 6 x + 9}{x - 3})

f (x) = (2 x - 5) (3 x + 1)

y^{^{'}} = \frac{x y ^{3}}{1 + x ^{2}}, y (0) = 1

\frac{\partial}{\partial x} (\frac{( 3 x - 4 y )}{- x + 6 y})

- \frac{x}{9 y}

What is the derivative of f(x)=x^2+2x ?
The derivative of f(x)=x^2+2x is 2x+2
What is the first derivative of f(x)=x^2+2x ?
The first derivative of f(x)=x^2+2x is 2x+2