What is the d/(dθ)(θ+cos(θ)) ?

The d/(dθ)(θ+cos(θ)) is 1-sin(θ)

What is the first d/(dθ)(θ+cos(θ)) ?

The first d/(dθ)(θ+cos(θ)) is 1-sin(θ)

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\frac{d}{d θ} (θ + cos (θ))

1 - sin (θ)

Solution steps

\frac{d}{d θ} (θ + cos (θ))

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d θ} (θ) + \frac{d}{d θ} (cos (θ))

\frac{d}{d θ} (θ) = 1

\frac{d}{d θ} (cos (θ)) = - sin (θ)

= 1 - sin (θ)

x \to 2 lim (\frac{x}{x ^{2} - 2 x})

\frac{\partial}{\partial x} ((- x^{4} + 7 x^{2} + 3 y)^{6})

(y - x y + x - 1) d x + x^{2} d y = 0

\int \frac{x + 49}{x} d x

\int \frac{x ^{3} ( 1 )}{1 - x ^{8}} d x