What is (\partial)/(\partial x)(x+3xy^2+x^2y) ?

The answer to (\partial)/(\partial x)(x+3xy^2+x^2y) is 1+3y^2+2yx

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(\partial)/(\partial x)(x+3xy^2+x^2y)

\frac{\partial}{\partial x} (x + 3 x y^{2} + x^{2} y)

1 + 3 y^{2} + 2 y x

Solution steps

\frac{\partial}{\partial x} (x + 3 x y^{2} + x^{2} y)

Treat

y

as a constant

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{\partial}{\partial x} (x) + \frac{\partial}{\partial x} (3 x y^{2}) + \frac{\partial}{\partial x} (x^{2} y)

\frac{\partial}{\partial x} (x) = 1

\frac{\partial}{\partial x} (3 x y^{2}) = 3 y^{2}

\frac{\partial}{\partial x} (x^{2} y) = 2 y x

= 1 + 3 y^{2} + 2 y x

\frac{1}{s ( s + 1 ) ^{3}}

\frac{x ^{3}}{x - 1}

\int_{0}^{1} \frac{21}{x ^{5}} d x

y^{^{''}} + y^{^{'}} + 5 y = 0

\int_{- 1}^{1} (x - 1) d x

What is (\partial)/(\partial x)(x+3xy^2+x^2y) ?
The answer to (\partial)/(\partial x)(x+3xy^2+x^2y) is 1+3y^2+2yx