What is the derivative of f(x)=2x^3 ?

The derivative of f(x)=2x^3 is 6x^2

What is the first derivative of f(x)=2x^3 ?

The first derivative of f(x)=2x^3 is 6x^2

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derivative of

f (x) = 2 x^{3}

6 x^{2}

Solution steps

\frac{d}{d x} (2 x^{3})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (x^{3})

Apply the Power Rule:

\frac{d}{d x} (x^{a}) = a \cdot x^{a - 1}

= 2 \cdot 3 x^{3 - 1}

Simplify

= 6 x^{2}

\int_{0}^{\frac{π}{4}} 5 tan^{3} (x) d x

t y^{^{'}} + 2 y = t^{2} - t + 1, y (1) = \frac{1}{2}

f (x) = (x^{3} + 2) (3 x^{2} - 4 x + 2), (1, 3)

\int \frac{3 x ^{2} + 3 x + 1}{x ^{3} + 2 x ^{2} + 2 x + 1} d x

(1, 2), (5, - 3)

What is the derivative of f(x)=2x^3 ?
The derivative of f(x)=2x^3 is 6x^2
What is the first derivative of f(x)=2x^3 ?
The first derivative of f(x)=2x^3 is 6x^2