What is the limit as x approaches 2 of (x-3)/(x^2-9) ?

The limit as x approaches 2 of (x-3)/(x^2-9) is 1/5

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limit as x approaches 2 of (x-3)/(x^2-9)

x \to 2 lim (\frac{x - 3}{x ^{2} - 9})

\frac{1}{5}

Decimal

0.2

Solution steps

x \to 2 lim (\frac{x - 3}{x ^{2} - 9})

Plug in the value

x = 2

= \frac{2 - 3}{2 ^{2} - 9}

Simplify

= \frac{1}{5}

\frac{d}{d x} (\frac{e ^{x}}{e ^{x} + e ^{y} + e ^{z}})

\frac{d y}{d x} = 3 x^{7} y - y, y (1) = - 9

y^{^{''}} + 4 y^{^{'}} + 4 y = 3 e^{- 2 x}

\int tan (a x) d x

\frac{d}{d x} (e^{s e c (x)})

What is the limit as x approaches 2 of (x-3)/(x^2-9) ?
The limit as x approaches 2 of (x-3)/(x^2-9) is 1/5