What is the tangent of 4/(sqrt(x)) ?

The tangent of 4/(sqrt(x)) is y=-2/(a_{0)^{3/2}}x+6/(sqrt(a_{0))}

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tangent of 4/(sqrt(x))

tangent of

\frac{4}{x}

y = - \frac{2}{a _{0}^{\frac{3}{2}}} x + \frac{6}{a _{0}}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, \frac{4}{a _{0}})

Find the slope of

y = \frac{4}{x} : \frac{d y}{d x} = - \frac{2}{x ^{\frac{3}{2}}}

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - \frac{2}{a _{0}^{\frac{3}{2}}}

Find the line with slope m=

- \frac{2}{a _{0}^{\frac{3}{2}}}

and passing through

(a_{0}, \frac{4}{a _{0}}) : y = - \frac{2}{a _{0}^{\frac{3}{2}}} x + \frac{6}{a _{0}}

y = - \frac{2}{a _{0}^{\frac{3}{2}}} x + \frac{6}{a _{0}}

y = x, at x = 81

f^{^{'}} (x) = x 7 - x^{2}

x \to 3 lim (77)

\int \frac{e ^{5}}{e ^{x}} d x

\int \frac{( cos ( x ) + sin ( x ) )}{sin ( 2 x )} d x

What is the tangent of 4/(sqrt(x)) ?
The tangent of 4/(sqrt(x)) is y=-2/(a_{0)^{3/2}}x+6/(sqrt(a_{0))}