What is the integral from 0 to 1 of sqrt(x) ?

The integral from 0 to 1 of sqrt(x) is 2/3

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integral from 0 to 1 of sqrt(x)

\int_{0}^{1} x d x

\frac{2}{3}

Decimal

0.66666 \dots

Solution steps

\int_{0}^{1} x d x

Apply the Power Rule

: [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{1}

= [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{1}

Compute the boundaries:

\frac{2}{3}

= \frac{2}{3}

y = x^{2} + 3 x

e^{3 x}, 1

arctan (\frac{1}{x})

f (x) = \frac{x ^{3} - x ^{2} - 1}{x ^{2}}

x \to - 2 lim (2 + x)

What is the integral from 0 to 1 of sqrt(x) ?
The integral from 0 to 1 of sqrt(x) is 2/3