What is the integral from 0 to infinity of x/(1+x^2) ?

The integral from 0 to infinity of x/(1+x^2) is diverges

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integral from 0 to infinity of x/(1+x^2)

\int_{0}^{\infty} \frac{x}{1 + x ^{2}} d x

diverges

Solution steps

\int_{0}^{\infty} \frac{x}{1 + x ^{2}} d x

Compute the indefinite integral:

\int \frac{x}{1 + x ^{2}} d x = \frac{1}{2} ln 1 + x^{2} + C

Compute the boundaries:

\int_{0}^{\infty} \frac{x}{1 + x ^{2}} d x =

diverges

= diverges

n = 1 \sum \infty \frac{6 ^{n}}{7 ^{n}}

6 e^{t}

\frac{d}{d x} (ln (tanh (\frac{x}{2})))

\int 7 (1 + tan^{2} (x)) d x

\frac{d}{d x} (e^{- a x})

What is the integral from 0 to infinity of x/(1+x^2) ?
The integral from 0 to infinity of x/(1+x^2) is diverges