What is the derivative of 2tsin(pit) ?

The derivative of 2tsin(pit) is 2(sin(pit)+pitcos(pit))

What is the first derivative of 2tsin(pit) ?

The first derivative of 2tsin(pit) is 2(sin(pit)+pitcos(pit))

Popular >

derivative of

2 t sin (π t)

2 (sin (π t) + π t cos (π t))

Solution steps

\frac{d}{d t} (2 t sin (π t))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d t} (t sin (π t))

Apply the Product Rule:

(f \cdot g)^{'} = f^{'} \cdot g + f \cdot g^{'}

f = t, g = sin (π t)

= 2 (\frac{d t}{d t} sin (π t) + \frac{d}{d t} (sin (π t)) t)

\frac{d t}{d t} = 1

\frac{d}{d t} (sin (π t)) = cos (π t) π

= 2 (1 \cdot sin (π t) + cos (π t) π t)

Simplify

= 2 (sin (π t) + π t cos (π t))

f (x) = x^{2} + 3 x + 2, at x = 3

\frac{d x}{d t} = \frac{x ^{3} - x t ^{2}}{t ^{3}}

h (x) = arcsec (2 x)

\frac{\partial}{\partial x} (x y^{2} - e^{y})

x \to 0 lim (x^{2} e^{- x})

What is the derivative of 2tsin(pit) ?
The derivative of 2tsin(pit) is 2(sin(pit)+pitcos(pit))
What is the first derivative of 2tsin(pit) ?
The first derivative of 2tsin(pit) is 2(sin(pit)+pitcos(pit))