What is the derivative of 1-2sin^2(x) ?

The derivative of 1-2sin^2(x) is -sin(2x)*2

What is the first derivative of 1-2sin^2(x) ?

The first derivative of 1-2sin^2(x) is -sin(2x)*2

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derivative of

1 - 2 sin^{2} (x)

- sin (2 x) \cdot 2

Solution steps

\frac{d}{d x} (1 - 2 sin^{2} (x))

Simplify

1 - 2 sin^{2} (x) : cos (2 x)

= \frac{d}{d x} (cos (2 x))

Apply the chain rule:

- sin (2 x) \frac{d}{d x} (2 x)

= - sin (2 x) \frac{d}{d x} (2 x)

\frac{d}{d x} (2 x) = 2

= - sin (2 x) \cdot 2

y = (\frac{x + 3}{x - 1})^{2}, (5, 4)

f (x) = sin (x) + arcsin (x)

\frac{d}{d x} (lo g_{2} (5 x))

\int \frac{3 + 2 x ^{2}}{x ^{2}} d x

\frac{d}{d x} (\frac{10}{x ^{3}})

What is the derivative of 1-2sin^2(x) ?
The derivative of 1-2sin^2(x) is -sin(2x)*2
What is the first derivative of 1-2sin^2(x) ?
The first derivative of 1-2sin^2(x) is -sin(2x)*2