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Popular >

ln(x)y^'= y/x

Solution

ln (x) y^{^{'}} = \frac{y}{x}

Solution

y = c_{1} ln (x)

Solution steps

ln (x) y^{'} (x) = \frac{y}{x}

Solve separable ODE:

y = c_{1} ln (x)

y = c_{1} ln (x)

Graph

Popular Examples

tangent of f(x)=sqrt(-x),\at x=-4 tangent of

f (x) = - x, at x = - 4

y^{^{''}} - 8 y^{^{'}} = 4 t

integral of (2x)/(x^2-16)

\int \frac{2 x}{x ^{2} - 16} d x

implicit (dy)/(dx),x^2+y^2=0 implicit derivative

\frac{d y}{d x}, x^{2} + y^{2} = 0

derivative of R(t)=(t+e^t)(3-sqrt(t))derivative of

R (t) = (t + e^{t}) (3 - t)

Frequently Asked Questions (FAQ)

What is the solution for ln(x)y^'= y/x ?
The solution for ln(x)y^'= y/x is y=c_{1}ln(x)