What is (\partial)/(\partial x)(ln(2x-y)) ?

The answer to (\partial)/(\partial x)(ln(2x-y)) is 2/(2x-y)

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(\partial)/(\partial x)(ln(2x-y))

\frac{\partial}{\partial x} (ln (2 x - y))

\frac{2}{2 x - y}

Solution steps

\frac{\partial}{\partial x} (ln (2 x - y))

Treat

y

as a constant

Apply the chain rule:

\frac{1}{2 x - y} \frac{\partial}{\partial x} (2 x - y)

= \frac{1}{2 x - y} \frac{\partial}{\partial x} (2 x - y)

\frac{\partial}{\partial x} (2 x - y) = 2

= \frac{1}{2 x - y} \cdot 2

Simplify

\frac{1}{2 x - y} \cdot 2 : \frac{2}{2 x - y}

= \frac{2}{2 x - y}

\int_{0}^{9} 9 + 3 x d x

3 t^{2}

y^{^{''}} - 4 y^{^{'}} + 53 y = 5 e^{2 t} cos (7 t)

cos^{10} (sin (7 x))

y = 4 x (3 x - 2)^{5}

What is (\partial)/(\partial x)(ln(2x-y)) ?
The answer to (\partial)/(\partial x)(ln(2x-y)) is 2/(2x-y)