What is the sum from n=0 to infinity of 1/(2^{n-1)} ?

The sum from n=0 to infinity of 1/(2^{n-1)} is converges

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sum from n=0 to infinity of 1/(2^{n-1)}

n = 0 \sum \infty \frac{1}{2 ^{n - 1}}

converges

Solution steps

n = 0 \sum \infty \frac{1}{2 ^{n - 1}}

Apply Series Ratio Test:

converges

= converges

\frac{x ^{4}}{2} - \frac{2}{x ^{4}} + 6 x

\frac{d}{d x} (arcsin (5 x - 1))

\int_{- 2}^{0} \frac{5}{x ^{2} + 4 x + 8} d x

x \to 4 lim (- x^{2} + 3 x - 7)

\frac{d}{d x} (\frac{π}{5})

What is the sum from n=0 to infinity of 1/(2^{n-1)} ?
The sum from n=0 to infinity of 1/(2^{n-1)} is converges