What is integral from 0 to 7 of f(x) ?

The answer to integral from 0 to 7 of f(x) is (49f)/2

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integral from 0 to 7 of f(x)

\int_{0}^{7} f (x) d x

\frac{49 f}{2}

Solution steps

\int_{0}^{7} f x d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{0}^{7} x d x

Apply the Power Rule

: [\frac{x ^{2}}{2}]_{0}^{7}

= f [\frac{x ^{2}}{2}]_{0}^{7}

Compute the boundaries:

\frac{49}{2}

= f \frac{49}{2}

Simplify

= \frac{49 f}{2}

θ \to 0 lim (\frac{sin ( 4 θ )}{θ})

f (x) = 8 x^{2} + 4 e^{- 0.5 x}

3 x

(x - y) d x + d y = 0

x \to 0 lim (\frac{g ( x )}{f ( x )})

What is integral from 0 to 7 of f(x) ?
The answer to integral from 0 to 7 of f(x) is (49f)/2