What is the tangent of f(x)=-3x^2 ?

The tangent of f(x)=-3x^2 is y=-6a_{0}x+3a_{0}^2

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tangent of f(x)=-3x^2

tangent of

f (x) = - 3 x^{2}

y = - 6 a_{0} x + 3 a_{0}^{2}

Solution steps

Compute the tangent line to the general point

x = a_{0}

Find the tangent point:

(a_{0}, - 3 a_{0}^{2})

Find the slope of

f (x) = - 3 x^{2} : \frac{df ( x )}{d x} = - 6 x

EN : T i tl e G e n er a l Eq u a t i o n Sl o p e A t P o in t 2 Eq : m = - 6 a_{0}

Find the line with slope m=

- 6 a_{0}

and passing through

(a_{0}, - 3 a_{0}^{2}) : y = - 6 a_{0} x + 3 a_{0}^{2}

y = - 6 a_{0} x + 3 a_{0}^{2}

\int_{0}^{1} x 2 - x^{2} d x

\int \frac{ln ( x + 5 )}{x + 5} d x

\frac{\partial}{\partial t} (2)

\frac{d y}{d x} + y^{2} = 0

x \to 3 lim (\frac{2 ^{x} - 8}{x - 3})

What is the tangent of f(x)=-3x^2 ?
The tangent of f(x)=-3x^2 is y=-6a_{0}x+3a_{0}^2