What is the solution for 4x^2y^{''}+17y=0 ?

The solution for 4x^2y^{''}+17y=0 is y=sqrt(x)(c_{1}cos(2ln(x))+c_{2}sin(2ln(x)))

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4x^2y^{''}+17y=0

4 x^{2} y^{^{''}} + 17 y = 0

y = x (c_{1} cos (2 ln (x)) + c_{2} sin (2 ln (x)))

Solution steps

4 x^{2} y^{''} (x) + 17 y = 0

Solve linear ODE:

y = x (c_{1} cos (2 ln (x)) + c_{2} sin (2 ln (x)))

y = x (c_{1} cos (2 ln (x)) + c_{2} sin (2 ln (x)))

f (, at)

y^{^{'}} + x y = - 5 x y^{4}

\int (x^{3} + 2 x) sin (x) d x

x \to 3 lim (7 + 6 (- 7))

\int 2 x + 9 d x

What is the solution for 4x^2y^{''}+17y=0 ?
The solution for 4x^2y^{''}+17y=0 is y=sqrt(x)(c_{1}cos(2ln(x))+c_{2}sin(2ln(x)))