What is the solution for (dx)/(dy)+1/(y^2)x= 1/(y^2) ?

The solution for (dx)/(dy)+1/(y^2)x= 1/(y^2) is x=e^{1/y+c_{1}}+1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dx)/(dy)+1/(y^2)x= 1/(y^2)

\frac{d x}{d y} + \frac{1}{y ^{2}} x = \frac{1}{y ^{2}}

x = e^{\frac{1}{y} + c_{1}} + 1

Solution steps

\frac{d x}{d y} + \frac{1}{y ^{2}} x = \frac{1}{y ^{2}}

Solve separable ODE:

x = e^{\frac{1}{y} + c_{1}} + 1

x = e^{\frac{1}{y} + c_{1}} + 1

f (x) = x^{2} (4 x^{3} - 1)

\int \frac{x ^{2} - 36}{x ^{4}} d x

\int_{1}^{2} (- 2 x + 6) d x

3 x^{2} + 2

y = (x^{2} + 3 x) 2

What is the solution for (dx)/(dy)+1/(y^2)x= 1/(y^2) ?
The solution for (dx)/(dy)+1/(y^2)x= 1/(y^2) is x=e^{1/y+c_{1}}+1