What is the integral from 0 to 6 of pi(36x^2-x^4) ?

The integral from 0 to 6 of pi(36x^2-x^4) is pi 5184/5

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integral from 0 to 6 of pi(36x^2-x^4)

\int_{0}^{6} π (36 x^{2} - x^{4}) d x

π \frac{5184}{5}

Decimal Notation

3257.20326 \dots

Solution steps

\int_{0}^{6} π (36 x^{2} - x^{4}) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= π \cdot \int_{0}^{6} 36 x^{2} - x^{4} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= π (\int_{0}^{6} 36 x^{2} d x - \int_{0}^{6} x^{4} d x)

\int_{0}^{6} 36 x^{2} d x = 2592

\int_{0}^{6} x^{4} d x = \frac{7776}{5}

= π (2592 - \frac{7776}{5})

Join

2592 - \frac{7776}{5} : \frac{5184}{5}

= π \frac{5184}{5}

x \to 0 lim ((ln (x))^{x})

\int \frac{x}{x - 3} d x

\int \frac{1}{2} cos (x) d x

\frac{d}{d x} (\frac{3 x}{x ^{3} + 7 x - 5})

f (x) = lo g_{2} (1 - 3 x)

What is the integral from 0 to 6 of pi(36x^2-x^4) ?
The integral from 0 to 6 of pi(36x^2-x^4) is pi 5184/5