What is the integral of (x/5)^n ?

The integral of (x/5)^n is (x^{n+1})/(5^n(n+1))+C

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integral of (x/5)^n

\int (\frac{x}{5})^{n} d x

\frac{x ^{n + 1}}{5 ^{n} ( n + 1 )} + C

Solution steps

\int (\frac{x}{5})^{n} d x

Apply exponent rule

= \int \frac{x ^{n}}{5 ^{n}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{5 ^{n}} \cdot \int x^{n} d x

Apply the Power Rule

: \frac{x ^{n + 1}}{n + 1}

= \frac{1}{5 ^{n}} \cdot \frac{x ^{n + 1}}{n + 1}

Simplify

\frac{1}{5 ^{n}} \cdot \frac{x ^{n + 1}}{n + 1} : \frac{x ^{n + 1}}{5 ^{n} ( n + 1 )}

= \frac{x ^{n + 1}}{5 ^{n} ( n + 1 )}

Add a constant to the solution

= \frac{x ^{n + 1}}{5 ^{n} ( n + 1 )} + C

\int_{- 1}^{1} 2^{x} d x

\frac{d}{d x} (2 + \frac{3}{1 + ( x + 1 ) ^{2}})

\frac{d}{d x} (8 x sin (x))

x \to - 3 + lim (\frac{x - 3}{x - 4})

\frac{d}{d x} (\frac{e ^{x^{2}}}{( 2 x + 1 ) ^{5}})

What is the integral of (x/5)^n ?
The integral of (x/5)^n is (x^{n+1})/(5^n(n+1))+C