What is the derivative of 2e^{-2x} ?

The derivative of 2e^{-2x} is -4e^{-2x}

What is the first derivative of 2e^{-2x} ?

The first derivative of 2e^{-2x} is -4e^{-2x}

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\frac{d}{d x} (2 e^{- 2 x})

- 4 e^{- 2 x}

Solution steps

\frac{d}{d x} (2 e^{- 2 x})

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 2 \frac{d}{d x} (e^{- 2 x})

Apply the chain rule:

e^{- 2 x} \frac{d}{d x} (- 2 x)

= e^{- 2 x} \frac{d}{d x} (- 2 x)

\frac{d}{d x} (- 2 x) = - 2

= 2 e^{- 2 x} (- 2)

Simplify

= - 4 e^{- 2 x}

\frac{d}{d x} (cos^{- 2} (x))

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f (x) = x^{3} - 9 x, at x = 3

\int (1 + \frac{1}{x})^{2} \frac{1}{x ^{2}} d x

\frac{d}{d x} (arccos (3 x + 1))

What is the derivative of 2e^{-2x} ?
The derivative of 2e^{-2x} is -4e^{-2x}
What is the first derivative of 2e^{-2x} ?
The first derivative of 2e^{-2x} is -4e^{-2x}