What is area 7x^2,x^2+4 ?

The answer to area 7x^2,x^2+4 is -(8sqrt(2))/(3sqrt(3))+8sqrt(2/3)

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area 7x^2,x^2+4

area

7 x^{2}, x^{2} + 4

- \frac{8 2}{3 3} + 8 \frac{2}{3}

Decimal Notation

4.35464 \dots

Solution steps

Apply the area formula:

\int_{- \frac{2}{3}}^{\frac{2}{3}} 7 x^{2} - (x^{2} + 4) d x

Solve

\int_{- \frac{2}{3}}^{\frac{2}{3}} 7 x^{2} - (x^{2} + 4) d x : - \frac{8 2}{3 3} + 8 \frac{2}{3}

The area is:

= - \frac{8 2}{3 3} + 8 \frac{2}{3}

x \to \infty lim (x - x)

\int_{0}^{1} x^{3} (2 x^{4} + 1)^{2} d x

\int \frac{cos ^{2} ( x )}{x} d x

\frac{d ^{3}}{d x ^{3}} (\frac{2}{x})

\int_{1}^{2} \frac{4}{x ^{3} + x} d x

What is area 7x^2,x^2+4 ?
The answer to area 7x^2,x^2+4 is -(8sqrt(2))/(3sqrt(3))+8sqrt(2/3)