What is the tangent of f(x)=sin(sin(x)),\at x=(4pi) ?

The tangent of f(x)=sin(sin(x)),\at x=(4pi) is y=x-4pi

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tangent of f(x)=sin(sin(x)),\at x=(4pi)

tangent of

f (x) = sin (sin (x)), at x = (4 π)

y = x - 4 π

Solution steps

Find the tangent point:

(4 π, sin (0))

Find the slope of

f (x) = sin (sin (x)) : \frac{df ( x )}{d x} = cos (sin (x)) cos (x)

Compute the slope of

f (x) = sin (sin (x))

x = 4 π : m = 1

Find the line with slope m=

1

and passing through

(4 π, sin (0)) : y = x - 4 π

y = x - 4 π

\int cos (2 x) + 1 d x

\int 3 e^{2 t} d t

\int 6 e^{5 x + e^{5 x}} d x

\frac{d}{d y} (- \frac{x}{y})

What is the tangent of f(x)=sin(sin(x)),\at x=(4pi) ?
The tangent of f(x)=sin(sin(x)),\at x=(4pi) is y=x-4pi